Fundamental Operations | Math | Chapter 4 | Grade 5 | With Exercises Solution

Fundamental operations math chapter 4 grade 5 exercise solution

by Math Sanjal

Fundamental Operations

Objectives:

Student will be able to:
Understand the correct way of using an operation.
Understand sign values.
Select appropriate order of operation for solving problems.
Understand connections between different operations.
Simplify the problems having different mathematical notations and different types of brackets.

Outcomes:

Students will have learnt to simplify the mathematical operations by using the proper order of operations.

Materials:

Multiplication chart, division chart, different vessels of different capacity etc...

Things to remember:

Fundamental Operations-
Addition, Subtraction, Multiplication and Division are the four fundamental operations in mathematics.
Addition rule: Numbers with same signs are added and carries the same sign as they were. Numbers with different signs are subtracted and the answer carries the sign of greater number.
Multiplication and Division rule: The product or quotient of two numbers of same signs will be positive but the product or quotient of two numbers of opposite signs are negative.
We use DMAS rule to simplify the problems related to number operation.
BODMAS rule is applied to solve the number operations within brackets.

Grade 5: Math Subject-Chapter:4 - Exercise 4.1 (With Solution)/button

1. Add the following numbers.

2. Add the following numbers horizontally.
Examples:

Please do as above. We will just write only the answers of rest. :)

a. 444+66,666
Solution: 67110

b. 10099+57899

Solution: 67998

c. 29,999+3,67,815

Solution: 3,97,814

d. 64,75,892+44,63,738

Solution: 1,09,39,630

e. 29,46,535+61,42,321

Solution: 90,88,856

f. 38,675+38,67,521+3,86,75,219

Solution: 4,25,81,415

g. 58,92,053+26,03,587+47,63,508

Solution: 1,32,59,148

h. 78,02,435+58,53,635+97,63,850

Solution: 2,34,19,920

i. 43,87,151+42,77,913+11,00,895

Solution: 97,65,959

j. 6,87,02,435+58,53,635+9,75,86,230

Solution: 17,21,42,300

Also Check:

3. Subtract the following numbers.

j. 3,25,078-22,969

Solution: 3,02,109

k. 7,57,87,980-6,16,86,995

Solution: 1,41,00,985

l. 3,23,84,647-1,69,99,998

Solution: 1,53,84,649

4. Solve the following problems.

a. There are 32 boys and 28 girls in grade five. Find the total number of students.

Solution:

Here,

Total number of boys in grade 5 = 32.

Total number of girls in grade 5 = 28.

So, the total number of students in class 5 are 32+28 = 60.

b. In a Bungmati VDC, there were 16,588 men, 17,492 women and 3,690 children. Find the total population of that village.

Solution:

Here,

Total number of men in Bungmati VDC = 16,588.

Total number of women in Bungmati VDC = 17,492.

Total number of children in Bungmati VDC = 3,690.

So, the total population of Bungmati VDC are 16,588+17,492+3,690 = 37,770.

c. According to the Nepal Census, 2068 B.S., male was 1,28,49041 and female was 1,36,45,469. What was the total population of 2068 B.S.?

Solution:

Here,

Total number of male = 1,28,49041.

Total number of female = 1,36,45,469.

So, the total population of 2068 B.S. are 1,28,49,041 + 1,36,45,469 = 2,64,94,510.

d. The aerial distance from Delhi to Moscow is 2,719 miles and from Moscow to California is 5,820 miles. If an aeroplane flies from Delhi to Moscow and Moscow to California, how much distance does it travel?

Solution:

Here,

Total distance from Delhi to Moscow = 2,719 miles.

Total distance from Moscow to California = 5,820 miles.

So, the total distance travel by aeroplane is 2,719 miles + 5,820 miles = 8,539 miles.

e. The peak of Mt. Everest from the base camp is 3,484 m. Tenjing climbs up 638 m in the first day, 715 m in the second day, 499 m in the third day and 850 m in the fourth day. If he plans to reach the peak in the fifth day, how high does he climb on fifth day?

Solution:

Here,

The height from the base camp to the peak of Mt. Everest = 3,484 m.

Tenjing climbs in first day = 638 m.

Tenjing climbs in second day = 715 m.

Tenjing climbs in third day = 499 m.

Tenjing climbs in fourth day = 850 m.

Tenjing climbs in fifth day = ?

Now,

Total height climbed upto fourth day by Tenjing = 638 m + 715 m + 499 m + 850 m = 2,702 m.

Therefore, Tenjing climbs = 3,484 m - 2,702 m = 782 m high in fifth day.

f. The total area of Nepal is 1,47,181 square kilometer.
The total area of the forest is 36,360 square kilometer.

Find the area of the land that is not covered by forest.

Solution:

Here,

The total area of Nepal = 1,47,181 square kilometer.

The total area of the forest = 36,360 square kilometer.

The total area of the land = ?

So, the total area of land that is not covered by forest is 1,47,181 - 36,360 = 1,10,821 square kilometer.

5. Find the difference between the following numbers.

a. 63,580 and 46,588

Solution: 63,580 - 46,588 = 16,992.

b. 32,158 and 4,93,298

Solution: 4,93,298 - 32,158 = 4,61,140.

c. 1,64,864 and 7,65,801

Solution: 7,65,801 - 1,64,864 = 6,00,937.

d. 9,99,999 and 10,90,859

Solution: 10,90,859 - 9,99,999 = 90,860.

e. 1,11,11,111 and 99,99,999

Solution: 1,11,11,111 - 99,99,999 = 11,11,112.

f. 10,00,008 and 8,99,999

Solution: 10,00,008 - 8,99,999 = 1,00,009.

6. The sum of two number is 689. If one number is 308, find another number.

Solution:

Here,

The sum of two number = 689.

One number = 308.

Another number = ?

So, another number is 689 - 308 = 381.

7. The total number of chicken in a farm were 3,86,528. Out of them 2,99,908 chicken died due to bird-flue. How many chicken are left in that farm?

Solution:

Here,

Total number of chicken in a farm = 3,86,528.

Total number of died chicken = 2,99,908.

Left chicken = ?

So, the chickens left in a farm are 3,86,528 - 2,99,908 = 86,620.

8. What should be added to 2,338 to get 9,750?

Solution:

Here,

9,750 - 2,338 = 7,412.

So, 7,412 should be added to 2,338 to get 9,750.

9. What should be subtracted from 9,65,380 to get 3,67,608?

Solution:

Here,

9,65,380 - 3,67,608 = 5,97,772.

So, 5,97,772 should be subtracted from 9,65,380 to get 3,67,608.

10. Find the difference of seven lakh seventeen thousand three hundred eight and five lakh ninety one thousand six hundred and eighty eight. Again, what should be added to this difference to get four lakhs eighteen thousand?

Solution:

Here,

Seven lakh seventeen thousand three hundred eight = 7,17,308.

Five lakh ninety one thousand six hundred and eighty eight = 5,91,680.

The difference of 7,17,308 and 5,91,680 is 7,17,308 - 5,91,680 = 1,25,628.

Now,

Four lakhs eighteen thousand = 4,18,000.

4,18,000 - 1,25,628 = 2,92,372.

So, 2,92,372 should be added to the difference to get four lakhs eighteen thousand.

Search Terms:/button

[alert]Fundamental Operations Grade 5 Exercises Solution., Grade 5 Math Exercises and Solution of Fundamental Operations., What are fundamental operations in math?, Math Addition rules Class 5., Math Multiplication and Division rules Class 5., DMAS and BODMAS rules Grade-Class 5 Math subject., Grade 5 Math Chapter 4 Exercise 4.1 Solutions., Math exercise 4.1 Solution of Grade/Class 5.[/alert]

Tags

Grade 5 Math Notes

Math Sanjal

Math is FUN. Learning Math isn't that easy but Following our Tutor and being with us, you will definitely become a Math Genius. :)

Comments

MathSanjal Comment Policy

We welcome relevant and respectful comments. Off-topic comments and spamming links may be removed.

Please read our Comment Policy before commenting.

Newer Posts Older Posts